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Given points: (6, 11), (3, 10)
Find: the equation of the line that passes through the given points Solution: First, wee need to find the slope m of the line, and then we can use one of the given points in the point-slope form of the equation of a line. After that you can transform it into the general form of the equation of a line. Let (x1, y1) = (3, 10), and (x2, y2) = (6, 11) slope = m = (y2 - y1)/(x2 - x1) = (11 - 10)/(6 - 3) = 1/3 (y - y1) = m(x - x1)
y - 10 = (1/3)(x - 3)
y - 10 = (1/3)x - 1
y - 10 + 10 - (1/3)x = (1/3)x - (1/3)x + 10 - 1
-(1/3)x + y = 9 which is the general form of the required line.
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