0
What else can I help you with?
How do you write an equation of the line that passes through the points. (2 5) (0 5)?
Points: (2, 5) and (0, 5) Slope: 0 Equation: x = 2 meaning that it is a straight horizontal line parallel to the y axis
What are the solutions to the equation 3x2-13x-10 equals 0?
(3x + 2)(x - 5) = 0 x = -2/3 or 5
What is the equation of x equals 2 over 3 and x equals 5 over 7 showing work?
If: x = 2/3 and x = 5/7 Then: (3x-2)(7x-5) = 0 Equation: 21x2-29x+10 = 0
Is 3x4 plus 2x plus 5 equals 0 a quadratic equation?
No. It is a quartic equation. The largest power of x in a quadratic equation must be 2.
What is the equation for The product of 5 and the sum of 8 and 2?
find the sum and product of the roots of 8×2+4×+5=0
3b2 plus b-10 equals 0?
3b2 + b - 10 = 0 This quadratic equation can be factored. (3b -5)(b +2) = 0 The equation can be solved when either (3b - 5) = 0, or (b + 2) = 0. If 3b - 5 = 0 then 3b = 5 : b = 5/3 If b + 2 = 0 then b = -2 The roots or solutions to this equation are b = 5/3 and b = -2
What is the equation of the line that passes through the points 0 5 and 2 3?
Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5
How do you write an equation of the line that passes through the points. (2 5) (0 5)?
Points: (2, 5) and (0, 5) Slope: 0 Equation: x = 2 meaning that it is a straight horizontal line parallel to the y axis
What is the correct equation of (0 1) (2 5) (3 7)?
To determine the correct equation for the points (0, 1), (2, 5), and (3, 7), we can first find the slope between two of the points, for example, (0, 1) and (2, 5). The slope is (5 - 1) / (2 - 0) = 2. The equation of the line in slope-intercept form (y = mx + b) is then y = 2x + 1. This equation can be checked with the other points to confirm its validity.
What is the equation of a line in general form that passes through points (-1 2) and (5 2)?
Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2
What are the solutions to the equation 3x2-13x-10 equals 0?
(3x + 2)(x - 5) = 0 x = -2/3 or 5
What is the equation for this line 0-2 20 42?
Points: (0, -2) and (20, 42) Slope: 11/5 Equation: 5y = 11x-10 or as y = 2.2x-2.
What is the equation of the circle that touches the x axis when its center is at 2 5?
Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25
What is the equation of x equals 2 over 3 and x equals 5 over 7 showing work?
If: x = 2/3 and x = 5/7 Then: (3x-2)(7x-5) = 0 Equation: 21x2-29x+10 = 0
Y equals -5x plus 5 and 3x plus 2y equals 3 solve this equation using substitution?
y = -5x+5 (Equation 1)3x+2y = 3 (Equation 2)you see the the first equation is equal to y. just put that into the second equation.3x + 2(-5x+5) = 3 (now do algebra and find x)3x - 10x + 10 = 3-7x = -7-x = -1x = 1Now put x into one of the equations to find yy = -5(1) + 5 (Equation 1)y = -5 + 5y = 0Now put both the x and y into both equations to see if it is truee.0 = -5(1) + 5 (Equation 1)0 = -5 + 50 = 0 CORRECT3(1) + 2(0) = 3 (Equation 2)3 + 0 = 33 = 3 CORRECTTherefore your answers arex = 1y = 0
What is 2x3 plus 11x equals 6x?
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
What is the perpendicular bisector equation of the line whose coordinates are -4 8 and 0 -2 on the Cartesian plane showing work?
Points: (-4, 8) and (0, -2) Slope: (8--2)/((-4-0) = -5/2 Perpendicular slope: 2/5 Midpoint: (-4+0)/2, (8-2)/2 = (-2, 3) Equation: y-3 = 2/5(x--2) Multiply all terms by 5: 5y-15 = 2(x--2) => 5y = 2x+19 Perpendicular bisector equation in its general form: 2x-5y+19 = 0
