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Points: (-1, 7) and (-2, 3)

Slope: 4

Equation: y = 4x+11

Q: What is the equation of the line in point-slope form that passes through the points -1 7 and -2 3?

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Write the equation of the line that passes through the points (3, -5) and (-4, -5)

Y= -3x + 8

Points: (6, -3) and (-4, -9) Slope: 3/5 Equation: 5y = 3x-33

Points: (2, 5) and (4, 3) Slope: -1 Equation: y = -x+7

Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6

Related questions

Write the equation of the line that passes through the points (3, -5) and (-4, -5)

The equation for the given points is y = x+4 in slope intercept form

If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6

Y= -3x + 8

It is y = 2.

Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.

Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5

If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x

In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.

Answer this question…y = 2x + 6

If the points are (1,5) and (0,0) y = 5x

Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32