A line through point (X, Y) with slope m has equation: y - Y = m(x - X)
→ line through (1, -1) with slope -3 has equation:
y - -1 = -3(x - 1)
→ y + 1 = -3x + 3
→ y + 3x = 2
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Point: (1, 4) Slope: -3 Equation: y = -3x+7
p (2,-1) and slope 3
which equation has a slope of -1/2 and a graph that passes through (-3,4)?
Y=mx+b
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
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Point: (1, 4) Slope: -3 Equation: y = -3x+7
Point: (2, 17)Slope: 7Equation: y = 2x+13
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
If you mean a point of: (-4, 7) and a slope of 4 Then the equation works out as: y = 4x+23
The equation is: y = 4x-22
Slope=8 point=(-7,3)
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
y = 7
y = 5