If the original line has the equation 2y = 7x then this can be written as y = 3.5x and the slope of this line is thus 3.5.
Two straight lines are perpendicular if the product of their gradients is -1.
Let m be the slope of the perpendicular line then, 3.5m = -1 : m = -1/3.5 = -2/7
The equation of the perpendicular line is thus, y = -2/7 * x + b where b is the intercept. As b = 5 then the equation becomes y = -2/7*x + 5
We can multiply by 7 to eliminate the fraction, 7y = -2x + 35
and re-order the terms to become 7y = 35 - 2x
y=-x
y equals -1/3x plus 4/3
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2y = -6x +8 y = -3x +4 The slope of the perpendicular is the positive reciprocal of -3 ahich is 1/3. So the equation is: y = 1/3x +5 If you mean that the y intercept is -5 then just change it.
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y = - 1/3 x + any number.
y=-x
y equals -1/3x plus 4/3
It would be perpendicular to a line with the equation Y = 1/8 X.
y = 1/3x+4/3
Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2. Two straight lines are perpendicular if the product of their gradients is -1. Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5 The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3 The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15
"Y = any number" is perpendicular to "x = -3".
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
It could be y = -x+5
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
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