If ' z ' is greater than ' 1 ', then ' z ' is. If ' z ' is less than ' 1 ', then ' 1 ' is.
(z=-3) and (z=7)
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
Thee of them which are 14x, -x and 2x = 15x
use the quadratic formula. when done so the roots are z=-3, and z=-6
z^2
This is a difference of two sqaures. 49y2 - z2 = (7y - z)(7y + z)
6xyz(3x + 2y + z)
If ' z ' is greater than ' 1 ', then ' z ' is. If ' z ' is less than ' 1 ', then ' 1 ' is.
4z squared (z+4) (z+4)
156 your welcome
x squared + y squared = z squared.
(z=-3) and (z=7)
(z-9)(z+3
No.
re x and y and hypotenuse z then x squared + y squared = z squared If you know x and z, then y sqrd = z sqrd-x sqrd and thus y = square root of (z sqrd -x sqrd)
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)