I am assuming the you are talking about the graph of the derivative. The graph of the derivative of F(x) is the graph such that, for any x, the value of x on the graph of the derivative of F(x) is the slope at point x in F(x).
The discriminant is the expression under the square root of the quadratic formula.For a quadratic equation: f(x) = ax2 + bx + c = 0, can be solved by the quadratic formula:x = (-b +- sqrt(b2 - 4ac)) / (2a).So if you graph y = f(x) = ax2 + bx + c, then the values of x that solve [ f(x)=0 ] will yield y = 0. The discriminant (b2 - 4ac) will tell you something about the graph.(b2 - 4ac) > 0 : The square root will be a real number and the root of the equation will be two distinct real numbers, so the graph will cross the x-axis at two different points.(b2 - 4ac) = 0 : The square root will be zero and the roots of the equation will be a real number double root, so the graph will touch the x-axis at only one points.(b2 - 4ac) < 0 : The square root will be imaginary, and the roots of the equation will be two complex numbers, so the graph will not touch the x-axis.So by looking at the graph, you can tell if the discriminant is positive, negative, or zero.
a line graph
The graph of g(x) is the graph of f(x) shifted 6 units in the direction of positive x.
The y axis is going up on the graph and the x axis is going sideways on the graph
If y varies directly as x, then the graph of y against x must be a straight line through the origin.However, if y varies directly as the square of x, for example, then the graph of y against the square of x will be the straight line through the origin - not y against x.
They're exactly the same shape and size, but every point on the graph of the first one is 8 units directly below the corresponding point on the graph of the second one.
A graph of a ^2 looks like a capital "U" and a graph of a ^3 looks like "U" but the left side of the "U" is flipped over the x-axis.
You just have to plug in numbers for x and plot it on a graph. You can't have a square root of a negative number, so the graph starts at 0 and moves to the right. You'll have to use a calculator to get the decimal approximation for some of y values. x=0, y=0 x=1, y=1 x=2, y= square root of 2 x=3, y=square root of 3 x=4, y=2 x=5, y=square root of 5 etc...
Rotating the graph y = x² clockwise 90° about the origin gives the graph of: y² = x → y = ±√x Removing the negative part leaves: y = √x (Note: it is convention that the radical symbol (√) means the positive square root.)
g(x) = √(x - 16) The graph of g(x) = √(x - 16) has the same shape as the graph of f(x) = √x. However, it is shifted horizontally to the right 16 units. The graph of the function f(x)=square root(x) is made up of half a parabola (in the first quadrant) with directrix (16, 0), which opens rightward. The domain is [16,∞) and range [0, ∞).
I am assuming the you are talking about the graph of the derivative. The graph of the derivative of F(x) is the graph such that, for any x, the value of x on the graph of the derivative of F(x) is the slope at point x in F(x).
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
To translate the graph y = x to the graph of y = x - 6, shift the graph of y = x down 6 units.
graph x+4<5
a line graph