Q: What is the area of an equilateral triangle with side lengths of 6 inches?

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15.588 square inches.

Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches

The area is: 15.6 (15.58846) square inches.

62.354 inches2

The side length is 18.24 (18.23606) inches.

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18

Area is 339.48196 m2

If the sides are different lengths it ain't equilateral...

27.713 cm2

15.588 square inches.

Its area is 46.8 (46.76533) square inches.

21.20

Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.

Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches

27.713 square inches.

A triangle cannot have four lengths!

By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!