409610
32/4=8 For example: 00000000(16), 12345678(16), DEADBEEF(16), FFFFFFFF(16).
import java.util.Scanner; public class NumberSystem { public void displayConversion() { Scanner input = new Scanner(System.in); System.out.printf("%-20s%-20s%-20s%-20s\n", "Decimal", "Binary", "Octal", "Hexadecimal"); for ( int i = 1; i <= 256; i++ ) { String binary = Integer.toBinaryString(i); String octal = Integer.toOctalString(i); String hexadecimal = Integer.toHexString(i); System.out.format("%-20d%-20s%-20s%-20s\n", i, binary, octal, hexadecimal); } } // returns a string representation of the decimal number in binary public String toBinaryString( int dec ) { String binary = " "; while (dec >= 1 ) { int value = dec % 2; binary = value + binary; dec /= 2; } return binary; } //returns a string representation of the number in octal public String toOctalString( int dec ) { String octal = " "; while ( dec >= 1 ) { int value = dec % 8; octal = value + octal; dec /= 8; } return octal; } public String toHexString( int dec ) { String hexadecimal = " "; while ( dec >= 1 ) { int value = dec % 16; switch (value) { case 10: hexadecimal = "A" + hexadecimal; break; case 11: hexadecimal = "B" + hexadecimal; break; case 12: hexadecimal = "C" + hexadecimal; break; case 13: hexadecimal = "D" + hexadecimal; break; case 14: hexadecimal = "E" + hexadecimal; break; case 15: hexadecimal = "F" + hexadecimal; break; default: hexadecimal = value + hexadecimal; break; } dec /= 16; } return hexadecimal; } public static void main( String args[]) { NumberSystem apps = new NumberSystem(); apps.displayConversion(); } }
1110 = E
It is EIt is EIt is EIt is E
409610
These are the hexadecimal digits and their decimal equivalents: 0 = 0 1 = 1 ... 9 = 9 A = 10 B = 11 ... F = 15
Largest 8 bit unsigned number is 11111111 binary which is the number 255 in decimal. In hexadecimal 255 is represented as FF In octal 255 is represented as 377. The related link below will help.
No as 100000000 has more digits than 2500000 Remember; The highest value number has the highest amount of digits
One example of a base with a value above seven is the base-16 system, also known as hexadecimal. In hexadecimal, the base is 16 and uses the digits 0-9 and the letters A-F to represent values.
M=1000 anything larger requires a combination of numerals
The value in hexadecimal of the decimal number 999910 is F41E6.
DCE means: Data Carrier Equipment Hexadecimal value in decimal: 3192
15
Yes. We could use decimal notation but hexadecimal is more convenient because it requires fewer digits and more closely reflects the way the machine addresses memory using its native binary notation. For instance, a 64-bit address in decimal requires 20 decimal digits (including leading zeroes) but only 16 hexadecimal digits. Moreover, the hexadecimal value can be easily translated into the actual binary value used by the machine because each hex digit maps 1:1 with every nybble of the binary value. A nybble is half-a-byte (4-bits). Since each address typically represents an 8-bit byte, the value of that byte can also be expressed using just 2 hexadecimal digits (00 to FF) whereas decimal notation would require 3 digits (000 to 255). If we used decimal notation to present the contents of a block of memory, then we wouldn't be able to fit as many columns of data on the screen at once. More importantly, when we look at the contents of memory we're generally more interested in what the computer sees, and hexadecimal notation more closely reflects what the computer sees.
12.
Any base that is itself a power of 2 is easily converted to and from binary. With base 4, each digit represents 2 bits. With base 8 (octal), each digit represents 3 bits. And with base 16 (hexadecimal), each digit represents 4 bits. Thus two hexadecimal digits represent an 8-bit binary value. This is convenient because we typically refer to a unit of computer memory as an 8-bit byte, thus every byte value can be represented using just 2 hex digits. If we had a system with a 9-bit byte we'd use 3 octal digits instead. A 24-bit value can either be represented using 6 hex digits or 8 octal digits. To convert a hexadecimal value to binary, we simply consult the following table (note that 0x is the conventional prefix for a hexadecimal value): hex = binary 0x0 = 0000 0x1 = 0001 0x2 = 0010 0x3 = 0011 0x4 = 0100 0x5 = 0101 0x6 = 0110 0x7 = 0111 0x8 = 1000 0x9 = 1001 0xA = 1010 0xB = 1011 0xC = 1100 0xD = 1101 0xE = 1110 0xF = 1111 Here, hexadecimal digit 0xF has the binary value 1111, thus 0xFF would be 11111111. Note that the bit patterns are in the same order as the hexadecimal digits. Thus 0x0F becomes 00001111 and 0xF0 becomes 11110000. Knowing this, we can easily convert binary values into hexadecimal, we simply divide the binary value into groups of 4 bits and convert each group to the corresponding hex digit. Thus 101101001100 becomes B4C (1011=B, 0100=4 and 1100=C). If there aren't enough bits, we simply pad the first group with leading zeroes. We can use a similar technique to convert between octal and binary, we simply divide the bits into groups of 3: octal = binary 00 = 000 01 = 001 02 = 010 03 = 011 04 = 100 05 = 101 06 = 110 07 = 111 Note that a leading 0 is the conventional prefix for octal values. Thus binary value 100010 would be written 042 in octal to avoid confusion with 42 decimal.