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X1 plus y2?
4
Is the smallest LCM of a number is the number itself?
Umm, you're question seems to have been a bit garbled. If the question was meant to be: Is the LCM of a single number the number itself? In that case the answer is...N/A... LCM (Least Common Multiple) MUST be at least two numbers. Otherwise "common" has no meaning in the title and the least multiple of any number would be 1 x0 =1, x1 =x, etc...However, if the question was meant to be something like: If a number is a multiple of another number, is their LCM the larger number? In that case, yes.P.S. "Is the smallest lcm" is redundant. Smallest and least are identical in this situation.
The distance between points x1 y1 and 5 -5 is the square root of x1 plus 5 2 plus y1 - 52?
false
How do you use a variance-covariance matrix to obtain least squares estimates?
Suppose that you have simple two variable model: Y=b0+b1X1+e The least squares estimator for the slope coefficient, b1 can be obtained with b1=cov(X1,Y)/var(X1) the intercept term can be calculated from the means of X1 and Y b0=mean(Y)-b1*mean(X1) In a larger model, Y=b0+b1X1+b2X2+e the estimator for b1 can be found with b1=(cov(X1,Y)var(X2)-cov(X2,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) to find b2, simply swap the X1 and X2 terms in the above to get b2=(cov(X2,Y)var(X1)-cov(X1,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) Find the intercept with b0=mean(Y)-b1*mean(X1)-b2*mean(X2) Beyond two regressors, it just gets ugly.
What is the answer to Evaluate x1 - x-1 plus x0 for x equals 2?
shut up and do your hw
