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It is: 1056+2 = 1058 and 1058/23 = 46

Q: What least number must be added to 1056 so that the sum is completely divisible by 23?

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10056รท23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor&times; quotient so 10056-5=23&times;437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23&times;438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23

It is: 36 and so 960/48 = 20

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The least number divisible by 2, 3, 4, 5, 6, 9, and 10 is 180.

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10056รท23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor&times; quotient so 10056-5=23&times;437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23&times;438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23

9400รท65 gives144 quotient,40 remainder. 65ร145 =9425 25 is the least

It is 20 because 5220/180 = 29

Well 924 by 48 give 19 as quotient . 48*19 is 912; 48ร20 is 960. now 924 + 36 is 960 so 36 is

No. At least not completely. It is 455.5.

3500/42 give 83 quotient,14 remainder next possibility 42*84 =3528. 28 must be added to 3500 then only it will divisible by 42.now check the dividend 3528 with the following divisor 49,56,63 3528/49=72 divisible 3528/56=63 divisible 3528/63=56 divisible So 3528 is divisible by 42,49,63,56 So 28 must be added 28 is the

3000รท19 give 157 and 17 as quotient and remainder 19*157 = 2983 Next 19*158= 3002 3000+2 =3002 ans 2

It is: 36 and so 960/48 = 20

It is 8961 - W*int(8961/W)

the least number is 210 which is divisible by four different prime numbers.

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