sqrt(62 + 62 + 62 ) = sqrt(36*3) = sqrt(108) = 10.39 cm
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The longest diagonal of a 6 cm cube is: 10.39 cm
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
15 cm
The edge length of this cube is: 8 cm
nine 9 cm