The longest diagonal of a 6 cm cube is: 10.39 cm
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
15 cm
The edge length of this cube is: 8 cm
nine 9 cm
The longest diagonal of a 6 cm cube is: 10.39 cm
Use Pythagoras' theorem to find the length of the outer diagonal and then use this as the base for the inner diagonal (the longest length of the cube) 82+82 = 128 and the square root of this is 11.3137085 cm 11.31370852+82 = 192 and the square root of this is 13.85640646 cm The longest pencil is 13.85640646 or just under 14 cm
The diagonal will be 8.66 cm
It is 72 sq cm.
Using Pythagoras' theorem the longest exterior diagonal is 19.209 cm to 3 dp
The diagonal is 3.61cm
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
The diagonal is 8.602 cm
A box has no equation. There are different equations for its volume, its surface area, the longest (principal) diagonal.
The diagonal is 63.64 cm
The side length is 70.71 cm
Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 5.1 cm × √2 ≈ 7.2 cm