The longest diagonal of a 6 cm cube is: 10.39 cm
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
To find the area of a triangle, you use the formula: Area = 1/2 * base * height. In this case, the base is 12cm and the height is 6cm. Plugging these values into the formula, we get Area = 1/2 * 12cm * 6cm = 36 square centimeters. Therefore, the area of the triangle is 36 square centimeters.
24 square centimeters
The diagonal is 15.620 meters.
It is 72 sq cm.
36 square cm
36 cm2
The diagonal length of a square with a 900 square foot area is: 42.43 feet.
The area of square is : 100.0
The square's diagonal is 11.314 cm
Area = 6*9 = 54 square cm
36 cm area of the square
The longest diagonal of a 6 cm cube is: 10.39 cm
The area is 72 cm2
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
Its diagonal is 1 unit.