7
0x19BACDFE = 1×16⁷ + 9×16⁶ + 11×16⁵ + 10×16⁴ + 12×16³ + 13×16² + 15×16¹ + 14×16⁰ = 431672830
Plus 12 plus -13 plus plus 1 can be rewritten in mathematical terms as: 12+(-13)+1 or 12-13+1 12-13+1 =-1+1 =0
7
13
To subtract fractions, you need a common denominator. In this case, the common denominator is 16. So, 13/16 - 1/4 becomes (13/16) - (4/16), which simplifies to 9/16. Therefore, 13/16 subtracted by 1/4 is equal to 9/16.
1 5 6 8 10 11 12 13 The median (or middle number) is 9.
The median of 1 and 5 and 5 and 8 and 10 and 12 and 13 and 14 is I think it is 8 and a half.
Median = 15
The answer is 8.5
So first let's order the set: 4,8,12,12,15,16 The mode is 12, there are 2 of them and 1 of everything else. The median is also 12 and the mean is (4+8+12+12+15+16)/6
14. Put in order: {1, 6, 10, 12, 12, 13, 15, 19, 27, 31, 32, 40} There are 12 data items, so the median is the (12 + 1) ÷ 2 = 61/2th data item. As 61/2 is not a whole number, take the mean average of the 6th and 7th data items: 6th is 13, 7th is 15 ⇒ median = (13 + 15) ÷ 2 = 14
The middle two numbers are 8 and 10 so the median is 9.
2 1/16 + 1 3/4 =3 13/161 3/4 = 1 12/16thus: 21/16 + 13/4=21/16 +112/16= 3 13/16
The median is the middle of the list (when sorted). In this case 16. The sorted list is:1, 4, 9, 16, 25, 36, 49.
Set it up like this: (1+6)(12+13) = 7 x 25 = 175
Whatever you like. The median value for each of the following three sets is 10. For the set {1, 9, 11, 12}. the mean is 8.25, smaller than the median. For the set {1, 9, 15, 15}. the mean is 10, the same as the median. For the set {1, 9, 15, 16}. the mean is 10.25, larger than the median.
If you have an even number of data points, the median is the mean of the middle two. eg, the median of {1, 2, 4, 6, 8, 10, 12, 16} is (6 + 8) ÷ 2 = 7.