To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 12, 20, 28, 36, and 44. These are increasing by 8 each time. This means the second difference is constant, indicating a quadratic sequence. By calculating the second difference, we can determine the equation for the nth term. The nth term for this sequence is n^2 + 10.
10n + 1
2n^2-1
+9
Difference is 5,7,9,11,13 Second difference is 2 (2x)^2 gives 4,9,16,25 Difference between 2x^2 and sequence is -5 Thus, the nth term will be (2n)^2-5
The nth term is 7n-4 and so the next number in the sequence is 31
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
10n + 1
2n^2-1
31 - n
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term is 6n+1 and so the next term will be 31
+9
the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps
Difference is 5,7,9,11,13 Second difference is 2 (2x)^2 gives 4,9,16,25 Difference between 2x^2 and sequence is -5 Thus, the nth term will be (2n)^2-5
5 to 7 is 27 to 17 is 1017 to 19 is 219 to 29 is 1029 to 31 is 2there fore following the pattern the nth term is 4131 to 41 is 10
The nth term is 7n-4 and so the next number in the sequence is 31
tn = 1.5*n2 - 1.5*n + 1