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To find the nth term of the sequence -4, -1, 4, 11, 20, 31, we first identify the pattern in the differences between the terms: 3, 5, 7, 9, 11, which increases by 2 each time. This suggests a quadratic relationship. The nth term can be expressed as ( a_n = n^2 + n - 4 ). Thus, the nth term of the sequence is ( a_n = n^2 + n - 4 ).
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Nth term for 11 ,31,51,72?
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
What is the nth term formula for -4 -1 4 11 20 31?
To find the nth term formula for the sequence -4, -1, 4, 11, 20, 31, we first observe the differences between consecutive terms: 3, 5, 7, 9, 11, which are increasing by 2. This indicates a quadratic relationship. The nth term formula can be derived as ( a_n = n^2 + n - 4 ).
What is the nth term 1 4 10 19 31?
tn = 1.5*n2 - 1.5*n + 1
What is the nth term in the sequence 7 13 19 25 31?
The sequence given is an arithmetic sequence where each term increases by 6. To find the nth term, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Here, ( a_1 = 7 ) and ( d = 6 ). Thus, the nth term can be expressed as ( a_n = 7 + (n-1) \times 6 = 6n + 1 ).
What is the nth term for 23 15 7 -1 -9?
Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.
Nth term for 11 ,31,51,72?
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
What is the nth term formula for -4 -1 4 11 20 31?
To find the nth term formula for the sequence -4, -1, 4, 11, 20, 31, we first observe the differences between consecutive terms: 3, 5, 7, 9, 11, which are increasing by 2. This indicates a quadratic relationship. The nth term formula can be derived as ( a_n = n^2 + n - 4 ).
What is the nth term for -4 -1 4 11 20 31?
To find the nth term of the sequence -4, -1, 4, 11, 20, 31, we first determine the differences between consecutive terms: 3, 5, 7, 9, 11. The second differences are constant at 2, indicating a quadratic relationship. The nth term can be expressed as ( a_n = n^2 + n - 4 ). Thus, the nth term is ( a_n = n^2 + n - 4 ).
What is the nth term for 13 22 31 20 49?
+9
What is the nth term for the sequence minus1 4 11 20 31 44?
Difference is 5,7,9,11,13 Second difference is 2 (2x)^2 gives 4,9,16,25 Difference between 2x^2 and sequence is -5 Thus, the nth term will be (2n)^2-5
What is the nth term of 1 7 17 31 49?
2n^2-1
What is the nth term for 30292827?
31 - n
What is the nth term for 11 21 31 41?
10n + 1
What is the nth term for the sequence 10 17 24 31 38?
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
What is the nth term for the sequences 7 13 19 25?
The nth term is 6n+1 and so the next term will be 31
What is the nth term for the sequence 22 13 4 -5 -14?
the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps
What is the next term in the pattern 2 9 11 20 31?
63
