Assuming this is a linear or arithmetic sequence,
the nth term is Un = 31 - 8n.
But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
It is: nth term = 5-4n and so the next term will be -19
To find the nth term of the sequence 1, 7, 15, W, 37, 51, we first observe the differences between consecutive terms: 6, 8, W-15, 22, 14. The second differences are 2, W-23, 8, -8. Assuming W is consistent with the pattern, we can deduce that W must equal 23 for the differences to create a consistent second difference. Thus, the nth term can be represented by a quadratic formula, which can be derived from the differences.
The nth term is: 5-2n
The sequence 8, 15, 22, 29, 36 is an arithmetic sequence where each term increases by 7. The first term (a) is 8, and the common difference (d) is 7. The nth term can be expressed using the formula: ( a_n = a + (n-1) \cdot d ). Therefore, the nth term is ( a_n = 8 + (n-1) \cdot 7 = 7n + 1 ).
It is 4n -1 and so the next term will be 23
It is: nth term = 29-7n
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
It is: nth term = 5-4n and so the next term will be -19
The nth term is 4n-1 and so the next term will be 19
The nth term is -7n+29 and so the next term will be -6
Balls deep
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
The rule for the nth term is t(0) = 23 t(n) = mod[t(n-1) + 2n-1, 26] for n = 1, 2, 3, ...
Well, darling, the nth term for this sequence is 8n + 7. You just add 8 to each term to get the next one, simple as that. So, if you want the 100th term, just plug in n=100 and you'll get 807. Easy peasy lemon squeezy!
15(1)