f = 10n + (n - 1)^2
For n=10
f = 10(10) + (10 - 1)^2
f = 181
The sequence given is an arithmetic progression where each term increases by 3. The first term is 5. To find the 10th term, use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Thus, the 10th term is ( 5 + (10-1) \times 3 = 5 + 27 = 32 ).
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
560
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
10^(n-1)
The nth term is (2n - 12).
It is: nth term = -4n+14
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1
The nth term is 3n+7 and so the next number will be 22
The nth term is: 3n+1 and so the next number will be 16
The sequence given is an arithmetic progression where each term increases by 3. The first term is 5. To find the 10th term, use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Thus, the 10th term is ( 5 + (10-1) \times 3 = 5 + 27 = 32 ).
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
560
Well, darling, the nth term of 10, 16, 22, 28 is simply n multiplied by 6, then add 4. So if you're feeling adventurous and want to find the 10th term, just plug in n=10 and voila, you've got yourself 64. Keep it sassy and keep it real, honey!
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.