If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
It is: nth term = -4n+14
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The nth term is (2n - 12).
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
It is: nth term = -4n+14
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The nth term is (2n - 12).
The nth term is 18 -3n and so the next term will be 3
The nth term can be anything you like! However, the simplest poynomial that fits these points is given by the rule: Un = n2 + 2 for n = 1, 2, 3, ...
Well, since the nth term is 2n+6, therefore First term = 2(1)+6 =8 Second term is 2(2) +6 = 10 Third term is 2(3) +6 = 12 Hence, their some = S3=3(2(a)+(3-1)d)/2 ====>3(2(8)+2(2))/2 ====>3(20)/2=30 Which means that this is an arithmetic sequence where a=8 and d=2 What you need to do is replace (n) with the number of the term you want to find, and there is your answer.
what is the nth term of 4,5,6,7,8
x2-3=n
n-9+3