One possible solution is t(n)= [-4n3 + 21n2 - 16n + 18]/3
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If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
It is: nth term = -4n+14
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The nth term is (2n - 12).