One possible solution is t(n)= [-4n3 + 21n2 - 16n + 18]/3
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
It is: nth term = -4n+14
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The nth term is (2n - 12).
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
It is: nth term = -4n+14
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The nth term is (2n - 12).
The nth term is 18 -3n and so the next term will be 3
The nth term can be anything you like! However, the simplest poynomial that fits these points is given by the rule: Un = n2 + 2 for n = 1, 2, 3, ...
Well, since the nth term is 2n+6, therefore First term = 2(1)+6 =8 Second term is 2(2) +6 = 10 Third term is 2(3) +6 = 12 Hence, their some = S3=3(2(a)+(3-1)d)/2 ====>3(2(8)+2(2))/2 ====>3(20)/2=30 Which means that this is an arithmetic sequence where a=8 and d=2 What you need to do is replace (n) with the number of the term you want to find, and there is your answer.
x2-3=n
n-9+3
The nth term of the sequence is (n + 1)2 + 2.
The nth term is 9n-2