The problem is finding the next term
7 9 13 21 37 69 133 261......... nth
the first number aka the N1 = 7, N2 = 9, N3= 13,....... N7= 133,........Nth
The first number 7 +2 = 9, which is the second number NOTE: 21=2
the second number 9 + 4 = 13 NOTE: 22=4
the third 13 + 8 = 21 NOTE: 23=8
the fourth 21 +16 = 37 NOTE: 24=16
So, the pattern is Nm+2m= the next number in the pattern
Nth = Nth-1+2th-1
By: Rodney T. Anderson
nth term = 5 +8n
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
46n9
go ask your teacher and tell him hes dumb
1 +3 =4 +3+4 =11 +3+4+4 =22 +3+4+4+4 37 +3+4+4+4+4 .... u can c where i am goin here
nth term = 5 +8n
It is increasing by 4 and the nth term is 4n+1
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
46n9
37 - 9n
The nth term is 7n-3 and so the next term will be 39
The nth term is 7n-5 and so the 6th term will be 37
37
go ask your teacher and tell him hes dumb
1 +3 =4 +3+4 =11 +3+4+4 =22 +3+4+4+4 37 +3+4+4+4+4 .... u can c where i am goin here
To find the nth term of the sequence 1, 7, 15, W, 37, 51, we first observe the differences between consecutive terms: 6, 8, W-15, 22, 14. The second differences are 2, W-23, 8, -8. Assuming W is consistent with the pattern, we can deduce that W must equal 23 for the differences to create a consistent second difference. Thus, the nth term can be represented by a quadratic formula, which can be derived from the differences.
13/37