The problem is finding the next term
7 9 13 21 37 69 133 261......... nth
the first number aka the N1 = 7, N2 = 9, N3= 13,....... N7= 133,........Nth
The first number 7 +2 = 9, which is the second number NOTE: 21=2
the second number 9 + 4 = 13 NOTE: 22=4
the third 13 + 8 = 21 NOTE: 23=8
the fourth 21 +16 = 37 NOTE: 24=16
So, the pattern is Nm+2m= the next number in the pattern
Nth = Nth-1+2th-1
By: Rodney T. Anderson
nth term = 5 +8n
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
46n9
go ask your teacher and tell him hes dumb
1 +3 =4 +3+4 =11 +3+4+4 =22 +3+4+4+4 37 +3+4+4+4+4 .... u can c where i am goin here
nth term = 5 +8n
It is increasing by 4 and the nth term is 4n+1
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
46n9
37 - 9n
The nth term is 7n-3 and so the next term will be 39
The nth term is 7n-5 and so the 6th term will be 37
37
go ask your teacher and tell him hes dumb
13/37
There are infinitely many polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one. The rule based on the polynomial of lowest order is: U(n) = -8n + 3.
We note that the numbers rise by addition of ;7;7 between terms. Hence we can write 7n . The first term( n- 1) is '9' So we can write 7(1) + c = 9 7 + c = 9 c = 2 So the nth term becomes 7n + 2