To find the nth term for this sequence, we first need to identify the pattern. The differences between consecutive terms are 1, 2, 3, and 4, indicating an increasing increment. This suggests the sequence is following a quadratic pattern. By examining the second differences, we see they are constant at 1. This indicates a quadratic sequence, and the nth term can be expressed as Tn = n^2 + 1.
12 - 5(n-1)
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
2n(n+1)
12 - 5(n-1)
The nth term is 5n-3 and so the next term will be 22
5
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
tn=5n-3
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The Nth term in the series is [ 2N ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The given sequence 6, 8, 10, 12 is an arithmetic sequence with a common difference of 2 between each term. To find the nth term of an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1) is 6 and the common difference (d) is 2. So, the nth term (a_n = 6 + (n-1)2 = 2n + 4).
The nth term of the sequence is (n + 1)2 + 2.
multiplies by 2