0
What else can I help you with?
Nth term of the sequence 12 7 2 -3 .. I know what the next numbers in the sequence are but what is the expression for the nth term?
12 - 5(n-1)
what is the nth term for 12 10 8 6?
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
What is the nth term of -8 2 12 22?
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
What is the formula for the nth term in the sequence 3 6 12 24 48 96 192?
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
What is the nth term for 12 10 8 6 4?
The given sequence is decreasing by 2 each time, starting from 12. To find the nth term, we can use the formula for an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, (a_1 = 12), (d = -2), and we need to find the general formula for the nth term. Therefore, the nth term for the sequence 12 10 8 6 4 is (a_n = 12 + (n-1)(-2)), which simplifies to (a_n = 14 - 2n).
Nth term of the sequence 12 7 2 -3 .. I know what the next numbers in the sequence are but what is the expression for the nth term?
12 - 5(n-1)
What is the nth term for the sequence 0 4 12 24 40?
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
What is the nth term of the sequence 2 7 12 17?
The nth term is 5n-3 and so the next term will be 22
What is the nth term of this sequence 2 7 12 17 22?
5
what is the nth term for 12 10 8 6?
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
What is the nth term for the sequence 2 7 12 17 22?
tn=5n-3
What is the nth term of -8 2 12 22?
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
What is the formula for the nth term in the sequence 3 6 12 24 48 96 192?
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
How do you write the Nth term in the sequence 2 4 8 16?
The Nth term in the series is [ 2N ] .
What is the nth term for 12 10 8 6 4?
The given sequence is decreasing by 2 each time, starting from 12. To find the nth term, we can use the formula for an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, (a_1 = 12), (d = -2), and we need to find the general formula for the nth term. Therefore, the nth term for the sequence 12 10 8 6 4 is (a_n = 12 + (n-1)(-2)), which simplifies to (a_n = 14 - 2n).
What is the nth term for this sequence 3 5 9 15 23?
To find the nth term of a sequence, we first need to identify the pattern. In this case, the sequence appears to be increasing by consecutive odd numbers: 2, 4, 6, 8, and so on. This means the nth term can be represented by the formula n^2 + 2. So, the nth term for this sequence is n^2 + 2.
What is the formula for the nth term in the sequence 3 6 12 24 48 96 192 384?
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
