It seems that the term increases 5 at a time, so (if this tendency continues) it's quite clear that the sequence is of the form 5n+k, for some constant "k". With a little experimentation, you can find that "k" should be 2.
t(n) = 12*n + 5
7n - 4
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.
The nth term is: 3n+2 and so the next number will be 20
Just subtract 9.
The nth term is 5n-3 and so the next term will be 22
5
t(n) = 12*n + 5
tn=5n-3
It is: nth term = 35-9n
-11n + 17
To find the nth term of the sequence 9, 12, 17, 24, 33, we first look at the differences between consecutive terms: 3, 5, 7, and 9. These differences themselves increase by 2, indicating a quadratic relationship. We can derive the nth term formula as ( a_n = n^2 + 8n + 1 ). Thus, the nth term of the sequence can be expressed as ( a_n = n^2 + 8n + 1 ).
7n - 4
It is 4n+5 and so the next term will be 25
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.
The nth term is: 3n+2 and so the next number will be 20