The numbers are increasing by increments of 1 2 3 4 5 ..... and so the next number in the sequence will be 22
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
Well, darling, it looks like we're dealing with a sequence where each number is increasing by a prime number. The nth formula for this sequence would be n^2 + n + 7. So, if you plug in n=1, you get 8; n=2 gives you 11; n=3 spits out 16; and so on. Keep it sassy and stay fabulous, my friend!
It is 5n-4 and so the next term will be 21
5n+1
Un = 29 - 9n
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
tn = n2
Well, darling, it looks like we're dealing with a sequence where each number is increasing by a prime number. The nth formula for this sequence would be n^2 + n + 7. So, if you plug in n=1, you get 8; n=2 gives you 11; n=3 spits out 16; and so on. Keep it sassy and stay fabulous, my friend!
It is 5n-4 and so the next term will be 21
The given sequence is -1, -6, -11, -16, -21. To find the nth term, we can identify that the sequence decreases by 5 each time. Thus, the nth term can be expressed as: ( a_n = -1 - 5(n-1) ), which simplifies to ( a_n = -5n + 4 ).
5n+1
Tn = 1 + 3n
The given sequence is an arithmetic sequence where each term decreases by 5. The first term (a) is -1 and the common difference (d) is -5. The nth term can be calculated using the formula ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = -1 + (n-1)(-5) = -1 - 5(n-1) = -5n + 4 ).
To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
20-9x=n