Let's break it down:
"What is the two digit number ..."
x is the 10's place; y is the 1's place; and z is the answer.
10x + y = z
"... that is [equal to] 4 times the sum of its digits ..."
4(x + y) = 10x + y
"... The tens digit is [equal to] 3 less than the units [1's] digit ..."
x = y - 3
Break down the complex equation:
4x + 4y = 10x + y
3y = 6x
Substitute the other equation for x, because x = y - 3, and continue:
3y = 6(y - 3)
3y = 6y - 18
-3y = -18
-y = -6
y = 6
So 6 is y, the 1's number.
x = y - 3
x = 6 - 3
x = 3
And 3 is x, your 10's number. Almost there! Now find your final answer, z:
10x + y = z
10(3) + 6 = z
30 + 6 = z
36 = z
Your answer is 36.
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The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
What is the units digit of the least whole number greater than 1000 whose digits are all different?
If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.
84.42 or 42.21
When multiplying numbers with the same units digit, the units digit of the product is determined by the units digit of the base number raised to the power of the number of times it is being multiplied. In this case, since 7 is being multiplied 100 times, the units digit of the product will be the same as the units digit of 7^100. The units digit of 7^100 can be found by looking for a pattern in the units digits of powers of 7: 7^1 = 7, 7^2 = 49, 7^3 = 343, 7^4 = 2401, and so on. The pattern repeats every 4 powers, so the units digit of 7^100 will be the same as 7^4, which is 1. Therefore, the units digit of the product when one hundred 7's are multiplied is 1.