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The first number doesn't matter, just that the last three are the same as the first.

P(rolling the same as the number before) = 1/6

P(rolling the same number as the first three times = (1/6)3 = 1/216

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Q: What is the probability of rolling the same number 4 times?
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What is the probability of rolling the same number when three number cubes are rolled?

The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36


When rolling five dice what is the probability that all 5 dice will be the same number?

The probability of rolling the same number on five dice is (1/6)4, or about 0.0007716.


What is the probability of rolling the same number twice?

In 2 rolls, it's 1/6 = 162/3% if you don't care what the number is.If you name the number you want before rolling, it's 1/36 = 27/9%.


Gary rolls a cube numbered from 1 to 6 What is the probability that he will not roll an even number greater than 3?

Gary's chances of rolling either a 4 or a 6 are the same for any of the other numbers on the cube. The probability is 1 out of 3.


What is the probability that you will spin a 4 and roll a 4?

Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60