yes the coin is biased because it turned to heads 36 times.
Anyone can flip a coin four times so I say 100 percent probability. On the other maybe you should ask the odds of the results from four flips.
random coin flips and exponeous events
None, since that would imply that in 18 cases the coin did not show heads or tails!
They are HHT HTH and THH
A fair coin would be expected to land on heads 10 times on average.
Roughly half of the time, so about 350 times.
The probability of a heads is 1/2. The expected value of independent events is the number of runs times the probability of the desired result. So: 100*(1/2) = 50 heads
A fair coin would be expected to land on heads 75 times.
30 maybe but i say 35 or 31
75
1/2 or 0.5
the 25 cent coin is 94% steel, 3.8% copper and 2.2% nickel plating. How do you classify nickel?
Coin tosses are independent events. The probability of a head remains 1/2
28 times out of 50 as a percent is achieved thus (28/50)*100 = 56% (The coin would appear to be biased by the way).
It depends on the condition of the coin. There is a rating system that is used to classify the worth of old coins and it is based on the amount of wear and damage to the coin. Take it to a coin shop to get an idea.
This is a binomial probability distribution The probability of exactly 2 heads in 50 coin tosses of a fair coin is 1.08801856E-12. If you want to solve this for how many times 50 coin tosses it would take to equal 1 time for it to occur, take the reciprocal, which yields you would have to make 9.191019648E11 tosses of 50 times to get exactly 2 heads (this number is 919,101,964,800 or 919 billion times). If you assume 5 min for 50 tosses and 24 hr/day tossing the coin, it would take 8,743,360 years. That is the statistical analysis. As an engineer, looking at the above analysis, I would say it is almost impossible flipping the coin 50 times to get exactly 2 heads or I would not expect 2 heads on 50 coin tosses. So, to answer your question specifically, I would say none.