11 *9 = 99
The two consecutive odd integers having a product of 99 are 9 and 11.
An infinite number of ways. 99+9/9 (99+9/9)*9/9 (99+9/9)*99/99 (99+9/9)*999/999 (99+9/9)*9/9*9/9 etc
The answer is 6.99574217 × 1013
99 plus (99/99) = 100
No because the product of numbers is the same as multiplying them so 9*99 = 891
11 *9 = 99
99
20
The two consecutive odd integers having a product of 99 are 9 and 11.
9 and 11. 9x11=99
There's only one product of 9 and 11. It's 99 .
0. There are 9 multiples of 10 between 1 and 99, so 99 factorial is divisible by at least the 9th power of 10. Therefore the last 9 digits are 0.
9 and 11. 9*11=99 11-9=2 Seriously, put sometime into thinking through, it's not that hard.
An infinite number of ways. 99+9/9 (99+9/9)*9/9 (99+9/9)*99/99 (99+9/9)*999/999 (99+9/9)*9/9*9/9 etc
The answer is 6.99574217 × 1013
The product of 11/8 times 9/4 is 99/32