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Q: What is the property 53x plus 4 equals 15x plus 20?
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Solve for x 55x plus -3 equals 53x plus 7?

55x + (-3) = 53x + 7can be written as55x - 3 = 53x + 7subtract 53x from both sides2x - 3 = 7add three to both sides2x = 10divided both sides by 2x = 5


What is the answer of 3x-1 plus 10 equals 5?

3x-1+10 = 53x + 9 = 53x = 5 - 93x = -4x = -4/3


What is 7X squared plus 2X squared equal to?

It equals 53X- a number is squared when it is multiplied by itself, so 7X by 7X = 49X. 2X by 2X =4X, so 49X + 4X is 53X.


What is the solution of the equation 53x equals 15. round your answer to the nearest ten-thousandth?

53x =15 : x = 53/15 = 3.5333 (4dp)


What equals 53 by x?

53x or 5.3 by 10x or 530 by 0.1x


How can you check the solution to x plus 53x-?

It's not something that can have a SOLUTION unless it EQUALS something. x + 53x = 54x. Does 54x = 1? Then x = 1/54. Does 54x = 108? Then x = 2. etc.


What number plus 53 would equal 180?

Assuming the missing number as XX + 53 = 180X = 180 - 53X = 127127 is the Answer


How do you solve and check the equation 3x plus 5 equals 23?

3X + 5 = 23subtract 5 from each side3X + 5 - 5 = 23 - 53X = 18divide both sides integers by 3(3/3)X = 18/3X = 6=======check by inserting 6 where X is in original equation3(6) + 5 = 2318 + 5 = 2323 = 23========checks


9x minus 53 equals 6 divided by x?

9x-53=6/x 9x2-53x=6 9x2-53x-6=0 9x2+x-54x-6=0 x(9x+1)-6(9x+1)=0 (9x+1)x(x-6)=0 9x+1=0 or x-6=0 9x=-1 or x=6 x=-1/9 or x=6


What is the equation of the line that passes through the point (62) and has a slope of 53 in slope-intercept form?

Point of passage (6, 2) and a slope of 53 Equation: y-2 = 53(x-6) => y = 53x-316


Does X35 spelled backwords make you horney 53X think of the 5 as an S and the 3 as an E?

HaHa ofcourse it does who wouldn't get HORN3Y


How do you solve 1 - in parentheses 5 3x is less than 2 in parentheses x-5 then minus 7x?

Please restate your question, but use () and < in it, so that it will make more sense. Then it will be easier to answer. I assume you mean: 1 - 5(3x) < 2(x - 5) - 7x. (If it were 1 - (53x) < 2(x - 5) - 7x, there would have been no need for the first parentheses.) The first thing you would do is distribute both the 5 and the 2: 1 - 15x < 2x - 10 - 7x Combine like terms: 1 - 15x < -5x -10 Get rid of one of the x terms. We will get rid of the -15x by adding 15x to both sides. (Whatever you do to one side, you have to do to the equivalent to the other, and I will choose which one to get rid of by choosing the one that causes me to end up with a positive x term, if possible.) 1 < 10x - 10 Now we will get rid of the -10 by adding 10 to both sides. 11 < 10x Divide both sides by 10: 11/10 < x Flip the equation around (including the sign) so that the x term is on the left: x > 11/10.