3X + 5 = 23
subtract 5 from each side
3X + 5 - 5 = 23 - 5
3X = 18
divide both sides integers by 3
(3/3)X = 18/3
X = 6
=======check by inserting 6 where X is in original equation
3(6) + 5 = 23
18 + 5 = 23
23 = 23
========checks
z=pq
2z+6z+24=0 8z+24=0 8z= -24 z= - 3
why will the equations x+14=37 and x-14=37 have different solutions for x
Set up the equation and solve for z: 28 + z = 56 (next, subtract 28 from each side of the equaition to solve) z = 28
The solution consists of the infinite number of points on the line which is defined by y + x = 6.
k equals 5.6
5
you can not solve this equation
The equation does not have a solution.
27
-0.5
Solve the following equation for A : 2A/3 = 8 + 4A
You cannot solve one equation in two unknowns.
x = 6
y = 31
(2x)ysquared
h= -4