ur mom
It is x/9 - 7.
9/(x-5) is.
The divisor is 9. quotient x divisor + remainder = dividend ⇒ quotient x divisor = dividend - remainder ⇒ divisor = (dividend - remainder) ÷ quotient = (53 - 8) ÷ 5 = 45 ÷ 5 = 9
Find out what X is first. You can't answer that without an equation.
x/2 - 9 = 14 x/2 = 23 x = 23 x 2 x = 46
9/x
x/9
If x/3 = 9, then x = 27.
It is x/9 - 7.
Nine less than the quotient of two and a number ( x ) can be expressed mathematically as ( \frac{2}{x} - 9 ). This represents the result of dividing 2 by ( x ) and then subtracting 9 from that quotient.
9/(x-5) is.
The divisor is 9. quotient x divisor + remainder = dividend ⇒ quotient x divisor = dividend - remainder ⇒ divisor = (dividend - remainder) ÷ quotient = (53 - 8) ÷ 5 = 45 ÷ 5 = 9
(x/4)-9=5
let X = number quotient = x/4 x/4 + 9 = 12 x/4 = 3 x = 12
Find out what X is first. You can't answer that without an equation.
x/2 - 9 = 14 x/2 = 23 x = 23 x 2 x = 46
To find the quotient when (2x^2 + 3x - 9) is divided by (x^3), we note that the degree of the divisor (x^3) is greater than the degree of the dividend (2x^2 + 3x - 9). Therefore, the quotient is (0) since (x^3) cannot divide (2x^2 + 3x - 9) without resulting in a fractional expression.