US IQ standard Deviation is 16.
3.898717738 is the standard deviation.
If G is a random variable representing the gestation period, an it is assumed to have a normal distribution with the given mean and standard deviation, then Prob(250 < G < 282) = Prob(-1 < Z < 1) where Z has the standard normal distribution. = 0.6827 = 68.3%
How can I find out what is considered a 'good' IQ? I got a score of 118 and am wondering if that is normal or slightly above? Can anyone answer? Please email me directly: abigail.f.miller@gmail.com.Thank you in advance and I appreciate the help.Sincerely,AbigailIQ is a statistic based on standard deviation, that is how far the subject is from the baseline (or average). Each standard deviation is granted 12 or 16 points depending on the test. A single standard deviation is 68.2% of the popuation, meaning 68.2% of people have within 12-16 IQ points of 100. 100 being the baseline average.Assuming half fall above average and half fall below, this means that only 15.9% of the population has above a 112 or 116 IQ depending on the actual test scaling. So, in either case you are in the top 15.9% in regards to raw IQ.
The answer is about 16% Using the z-score formula(z = (x-u)/sd) the z score is 1. This means that we want the percentage above 1 standard deviation. We know from the 68-95-99.7 rule that 68 percent of all the data fall between -1 and 1 standard deviation so there must be about 16% that falls above 1 standard deviation.
US IQ standard Deviation is 16.
3.898717738 is the standard deviation.
It is 3.045
B because the spread, in this case standard deviation, is larger.
19
mean is 218 with a standard deviation of 16
16
The mean absolute deviation is 2
There are 16 trials.
Standard deviation is the square root of the mean. The mean for this set is (2 + 4 + 3 + 7)/4 = 16/4 = 4; the square root of this is 2.
average length from trough to trough of 46 months and standard deviation of 16 months.
9 15 15 15 16 (five data) Range = 16 - 9 = 7 Mean = (9 + 15 + 15 + 15 + 16)/5 = 70/5 = 14 So we have: (9 - 14)2 = (-5)2 = 25 (the square of the difference of data value and the mean value) (15 - 14)2 = 12 = 1, 3(1) = 3 (16 - 14)2 = 22 = 4, the sum is 32 The standard deviation = √(32/5) ≈ 2.5