Assuming that is: f(x) = 4x^2 + 24x + 4
Completing the square gives:
f(x) = (2x + 6)^2 - 32
Square numbers are always greater than or equal to 0, so the value of f(x) has a minimum value of -32.
There is no upper limit to a square number, so f(x) can have as positively large a value as you like.
Thus the range of f(x) is: f(x) ≥ -32.
If the assumption is wrong, please re-submit using words for plus, minus, equals, etc.
false!
No answers in integers, quadratic formula gives roots as 1.31 and -0.19
Y
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
No integer roots. Quadratic formula gives 1.55 and -0.81 to the nearest hundredth.
The quadratic 4x2+24x+11 = (2x+1)(2x+11)
The domain is from negative infinity to positive infinity. The range is from positive 2 to positive infinity.
y = -4x2 + 1 Range = {y:y=<1, y is an element of the reals}
No. [ y = 4x2 ] is a quadratic equation.
false!
4(x2 - 6x + 13)
All that can be said is that F(x) is a quadratic function of x, with two real roots.
If: x = -2 and x = 3/4 Then: (4x-3)(x+2) = 0 So: 4x2+5x-6 = 0
(2x - 1)(2x + 5)
4x2 + 6x - 3 (with no remainder)
-4x2 - 32x + x + 8 = 8x2 - 56x : simplify and group the various terms-32x + 56x + x + 8 = 8x2 + 4x225x + 8 = 12x2 : Now present this as a standard quadratic equation.12x2 - 25x - 8 = 0 : Solving for the roots of a quadratic equation gives :-x = [25 ± √(252 + 4x12x8)] ÷ 2x12 = [25 ± √1009] ÷ 24 = [25 ± 31.765] ÷ 24x = 56.765/24 = 2.365 and x = -6.765/24 = -0.282x = 2.365 and -0.282
Quadratic equation formula