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Assuming that is: f(x) = 4x^2 + 24x + 4

Completing the square gives:

f(x) = (2x + 6)^2 - 32

Square numbers are always greater than or equal to 0, so the value of f(x) has a minimum value of -32.

There is no upper limit to a square number, so f(x) can have as positively large a value as you like.

Thus the range of f(x) is: f(x) ≥ -32.

If the assumption is wrong, please re-submit using words for plus, minus, equals, etc.

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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals". It is, therefore not possible to say what the minimum value of the function is. The range has no upper bound.

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10y ago
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Q: What is the range of the quadratic function f(x) 4x2 24x 4?
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