Assuming that is: f(x) = 4x^2 + 24x + 4
Completing the square gives:
f(x) = (2x + 6)^2 - 32
Square numbers are always greater than or equal to 0, so the value of f(x) has a minimum value of -32.
There is no upper limit to a square number, so f(x) can have as positively large a value as you like.
Thus the range of f(x) is: f(x) ≥ -32.
If the assumption is wrong, please re-submit using words for plus, minus, equals, etc.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals". It is, therefore not possible to say what the minimum value of the function is. The range has no upper bound.
false!
No answers in integers, quadratic formula gives roots as 1.31 and -0.19
Y
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
No integer roots. Quadratic formula gives 1.55 and -0.81 to the nearest hundredth.
The quadratic 4x2+24x+11 = (2x+1)(2x+11)
The domain is from negative infinity to positive infinity. The range is from positive 2 to positive infinity.
y = -4x2 + 1 Range = {y:y=<1, y is an element of the reals}
false!
No. [ y = 4x2 ] is a quadratic equation.
4(x2 - 6x + 13)
All that can be said is that F(x) is a quadratic function of x, with two real roots.
If: x = -2 and x = 3/4 Then: (4x-3)(x+2) = 0 So: 4x2+5x-6 = 0
(2x - 1)(2x + 5)
4x2 + 6x - 3 (with no remainder)
-4x2 - 32x + x + 8 = 8x2 - 56x : simplify and group the various terms-32x + 56x + x + 8 = 8x2 + 4x225x + 8 = 12x2 : Now present this as a standard quadratic equation.12x2 - 25x - 8 = 0 : Solving for the roots of a quadratic equation gives :-x = [25 ± √(252 + 4x12x8)] ÷ 2x12 = [25 ± √1009] ÷ 24 = [25 ± 31.765] ÷ 24x = 56.765/24 = 2.365 and x = -6.765/24 = -0.282x = 2.365 and -0.282
you can factorise 5x2-24x-12 if you use the quadratic formula: This goes to (24(+/-)sqrt(816))/(10) =5.257 or -0.4566 (4s.f.)