Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
It is: y = -1/5x-2
Equation of original line is 4x + 3y - 5 = 0 that is, 3y = -4x + 5 or y = -(4/3)x + 5 Slope of original line = -4/3 Slope of line perpendicular to it = 3/4 General equation of perpendicular line: y = (3/4)x + c for some constant c or 4y = 3x + c' The point (-2,-3) is on this line so 4*(-3) = 3*(-2) + c' -12 = - 6 + c' so that c' = -6 The equation of the perpendicular line is 4y = 3x - 6
y = 0. You can get this from the slope-intercept equation of the line.
Without an equality sign and not knowing the plus or minus values of x and 4 the given terms can't be considered to be a straight line equation. Two lines that are parallel to each other will have the same slope but different y intercepts.
Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
3x-4y-6 = 0
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean 4x+y = 10 then y = -4x+10 and the parallel equation is y = -4x+6
It is: y = -1/5x-2
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation but in general parallel equations have the same slope but different y intercepts.
Equation of original line is 4x + 3y - 5 = 0 that is, 3y = -4x + 5 or y = -(4/3)x + 5 Slope of original line = -4/3 Slope of line perpendicular to it = 3/4 General equation of perpendicular line: y = (3/4)x + c for some constant c or 4y = 3x + c' The point (-2,-3) is on this line so 4*(-3) = 3*(-2) + c' -12 = - 6 + c' so that c' = -6 The equation of the perpendicular line is 4y = 3x - 6
What is the equation of the vertical line passing through (-5,-2)
the Equation of a Line Given That You Know Two Points it Passes Through.
It means then that the slope of the straight line equation will be minus
y = 3x+8 which can be expressed in the form of 3x-y+8 = 0
The equation of a horizontal line is of the form y=k, where k is the y-coordinate of the point through which the line passes. Therefore, the equation of the horizontal line through the point (8, -10) is y = -10.
y = 0. You can get this from the slope-intercept equation of the line.