If you divid 3 by 2 you get 1r1 3 goes into 2 once which is 2. 2-2=1 3 cant go into 1 so its 1 r1
1r1
3) 2
-2
1
58
you have to divide the remainder by the number you are dividing
501
26. This is because when you divide 26 by 5, you have a remainder of 1, and when you divide it by 4, you have a remainder of 2
the biggest remainder you can have when dividing by 2 is 1. Reason is ......if you divide an even number by 2 you will always get a round answer. However if you divide an odd number by 2 you will always get a full number with 1 reamining...i.e divide 3 by 2.........2 remainder 1......................divide 19 by 2 this will give you 9 remainder 1. Hope this helps
58
Not if you divide correctly.
The smallest whole number that can be divided by both 3 and 6 and leaves a remainder of 1 is 7.
361
450 is the smallest number that both 45 and 50 can divide into evenly with no remainder.
45 is the smallest number that both 9 and 15 divide into evenly with no remainder.
20 is the smallest number that both 4 and 10 will divide into evenly with no remainder.
Because 22 is the smallest number that both 2 and 11 divide into evenly with no remainder.
Because 30 is the smallest number that both 10 and 15 can divide into evenly with no remainder.
Because 33 is the smallest number that both 3 and 11 divide into evenly with no remainder.
21 is the smallest number that both 7 and 3 divide into evenly with no remainder.
The smallest number is LCM(2, 3, 4, 5, 6) + 1 = 61