(560 ÷ 25) − 0.4 = 22
Therefore, the smallest number to subtract from 560 is 0.4 * 25 = 10
sqrt(2493) = 49.93 So the largest perfect square smaller than 2493 is 492 = 2401 Therefore, the smallest number to be subtracted is 2493 - 2401 = 92
339 + 1 = 340,which is exactly divisible.
what least number must be subtracted from 13081 to get a number exactly divisible by 87
It is: 16 because 18448-16 = 18432 and 18432/48 = 384
3214682/487 gives 6600 as quotient 482 remainder. Dividend-remainder=divisor*quotient 3214682-482 gives 3214200 which is divisible by 487. 482 can be subracted there are more possibility
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
4.234,601 - 4 = 234597 (which is 11 * 21,327).
To determine the least number to be subtracted from 789 to make it divisible by 56, first, calculate the remainder when 789 is divided by 56. Performing the division, 789 ÷ 56 gives a quotient of 14 and a remainder of 5. To make 789 divisible by 56, subtract this remainder from 56, which is 56 - 5 = 51. Therefore, the least number to be subtracted from 789 is 51.
It is 1 because 734688/3 = 244896
sqrt(2493) = 49.93 So the largest perfect square smaller than 2493 is 492 = 2401 Therefore, the smallest number to be subtracted is 2493 - 2401 = 92
Answer = 18. 4848 - 18 = 4830 4830 / 46 = 105
It would help if you could insert the relevant numbers in the copy/paste!
339 + 1 = 340,which is exactly divisible.
To find the number that should be subtracted from 63700 to make it exactly divisible by 18, first, calculate the remainder when 63700 is divided by 18. Dividing 63700 by 18 gives a quotient of 3538 and a remainder of 16. Therefore, to make 63700 divisible by 18, you need to subtract this remainder (16) from 63700. Thus, subtracting 16 will yield 63684, which is divisible by 18.
what least number must be subtracted from 13081 to get a number exactly divisible by 87
6 (or 0)
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.