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If the question gives 4x-3=9, then we can solve: 4x-3=9 4x=6 x=3/2, or 1.5
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
The solution of 4x plus 3y -9 and x -3 is; 5x+3y-3.