If the question gives 4x-3=9, then we can solve: 4x-3=9 4x=6 x=3/2, or 1.5
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
The solution of 4x plus 3y -9 and x -3 is; 5x+3y-3.
If the question gives 4x-3=9, then we can solve: 4x-3=9 4x=6 x=3/2, or 1.5
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
Yes. It is THE solution.
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
The equation 4x + 5 = 2 has the solution 4x = -3 and x = - 3/4 (minus 3/4).
Yes, x = 2 is the solution.
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
It is: x = 5/3 and x = -3
They are: x = 5/3 and x = -3
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
4x2-4x-3 = 0 (2x-3)(2x+1) = 0 x = 3/2 or x = -1/2
the solution for the inequality 4x + 2 - 6x < -1 was x < 3/2