4x^2 - 11x + 6 = 0
(4x - 3)(x - 2)
x = 3/4, 2
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11x(2x - 1) = 0 so either 11x = 0 or x = ½
4x2 - x - 5 = 0 4x2 + 4x - 5x - 5 = 0 4x(x + 1) - 5(x + 1) = 0 (4x - 5)(x + 1) = 0 4x - 5 = 0 or x + 1 = 0 4x = 5 or x = -1 x = 5/4 o x = -1
8 (eight)
'x' must be zero, so the solution set is [ 0 ].
There are four solutions to 9x4 plus 27x3 - 4x2 - 12x equals 0. One of the solutions is x = -3.