sqrt(y*y) = sqrt(y2) =±
y
Do the multiplication, then take the square root. After the multiplication, you get 28x4y2. The square root of 28 is 2 times the root of 7, the square root of x4 is x2, and the root of y2 is y. So, the final result is 2 times square root of 7, times x2y.
square root (y) / Square root (3) root (y) / 1.73
y = sqrt X + 3sqrt X is the same as y = 4 sqrt X
x=y
98 is 49 times 2 so the square root of 98 is the square root of 49 times the square root of 2. But the square root of 49 is 7 , so the answer is 7 times the square root of 2.
5x times the square root of y
That can be true when "x" and "y" are both zero, or both 1.
Do the multiplication, then take the square root. After the multiplication, you get 28x4y2. The square root of 28 is 2 times the root of 7, the square root of x4 is x2, and the root of y2 is y. So, the final result is 2 times square root of 7, times x2y.
square root (y) / Square root (3) root (y) / 1.73
y = sqrt X + 3sqrt X is the same as y = 4 sqrt X
One step you usually want to take is to move any perfect square out of the radical. Example 1, with numbers: root(12) = root(4x3) = root(4) x root(3) = 2 root(3) Example 2, with variables: root(y cubed) = root(y squared times y) = root(y squared) times root(y) = y root(y)
A square root is taking a number X and determining which two same numbers times each other, or Y*Y equal X. If X equals 9, the square root of it is 3; that is 3 (Y) multiplied by 3 (Y) is 9.
x=y
log of the square root of 'y' = 1/2 sqrt(y)
y6
square root 2 times square root 3 times square root 8
X^1/2 + Y^1/2 Essentially it is just the square root of x plus the square root of y, there's no real way of simplifying that.