It is sqrt[(1-p)/p2] = 0.666... recurring.
The mean and standard deviation do not, by themselves, provide enough information to calculate probability. You also need to know the distribution of the variable in question.
The probability of scoring an exact value for a continuous variable is zero for any value. The probability of scoring 115 (or more) is 15.87%
The Poisson distribution is a discrete distribution, with random variable k, related to the number events. The discrete probability function (probability mass function) is given as: f(k; L) where L (lambda) is the mean and square root of lambda is the standard deviation, as given in the link below: http://en.wikipedia.org/wiki/Poisson_distribution
It is not. And that is because the mean deviation of ANY variable is 0 and you cannot divide by 0.
means equal the standard deviation
The mean and standard deviation do not, by themselves, provide enough information to calculate probability. You also need to know the distribution of the variable in question.
The probability of scoring an exact value for a continuous variable is zero for any value. The probability of scoring 115 (or more) is 15.87%
Approx 0.0027
30 percent.
3
The mean is 0.9592
It is the Standard normal variable.
a standardizing variable is a variable that has a mean of zero and a standard deviation of one .
The Poisson distribution is a discrete distribution, with random variable k, related to the number events. The discrete probability function (probability mass function) is given as: f(k; L) where L (lambda) is the mean and square root of lambda is the standard deviation, as given in the link below: http://en.wikipedia.org/wiki/Poisson_distribution
Time is a continuous variable and so the probability that an event takes any particular value is always 0.
.820=82.0%
The standard deviation has the same measurement units as the variable and is, therefore, more easily comprehended.