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Q: What is the substitution method for -x y-2?

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2x+7y=29 x=37-8y

-2

The distance between (x, y1) and (x, y2) is abs(y1 - y2) or |y1 - y2|.

3y2 y x y = y2 3 x y2 = 3y2

That's exactly the purpose of the substitution method ... to get an equation with one less variable. When you have it, you solve it for the variable that's left.

Related questions

y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2

x+y=5

Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1

0

x+2y = 30 => x= 30-2y x2+y2 =900 (30-2y)2+y2 = 900 (30-2y)(30-2y)+y2 = 900 900-60y-60y+4y2+y2 = 900 5y2-120y = 0 y(5y-120) = 0 y = 0 or y= 24 Substitute the value of y into the original equations to find the value of x: Therefore: x = -18 and y = 24 Check: -18+48 = 30 and (-18)2+242 = 900

Yes, as x-y2=0

The substitution method undoes the chain rule.

If you mean: y = 6x+11 and y = 2x+7 Then by substitution: x = -1 and y = 5

X2+y2=25 (x-8)2+y2 =41

2x-3y=13

If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3

What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2