the sum of 3 times m and n
Three times the difference of a and m divided by twice their sum is equal to 6(a squared - m squared). 3(a - m)/2(a + m)
Sum = 38 + M
The sum of -8 and 6 is -2
The sum of 8 and 6 is 14 (8+6)
The sum of "m" and 6 is "m + 6".
the sum of 3 times m and n
Three times the difference of a and m divided by twice their sum is equal to 6(a squared - m squared). 3(a - m)/2(a + m)
Sum = 16.4 m Product = 115.2 m3 Largest = 8 m Smallest = 2.4 m
If you mean 14=2m+2... then m=6
Convert the 6 km into m by multiplying by 10006 km = 6000 mAdd 2 values together6000 m + 320 m = 6320 m
Sum = 38 + M
Let the numbers be m & m+1 (consecutive) Hence their squares are m^2 & ( m + 1)^2 => m^2 & m^2 + 2m + 2 Hence Their sum is m^2 + m^2 + 2m + 1 = 85 2m^2 + 2m - 84 = 0 m^2 + m - 42 =0 Factor (m + 7)(m - 6) = 0 Hence the numbers are 6 & 7 .
the sum of m and 9 is 9+m
it's codes in c# console Apllication is : int a, m, sum; sum = 0; for (a = 1; a <= 1000; a++) { m = 1; while (m <= a) { if (a % m sum) Console.WriteLine(a.ToString()); sum = 0; } Console.ReadLine();
mn = 8 ( Product) m + n = 6 (Sum) Hence m = 6 - n Substitute (6 -n)n = 8 Multiply out the brackets 6n - n^(2) = 8 n^(2) - 6n + 8 = 0 It is now in quadratic form and will factor Hence ((n - 2)(n - 4) = 0 n = 2 & n = 4 So '2' & '4' are the two numbers. Verification 2 + 4 = 6 2 x 4 = 8
m + 8