The sum of 9 odd numbers must be odd and so cannot be an number.
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
The sum of the first 50 whole numbers is 1,225.
Using the formula for the sum of an arithmetic sequence;Sum = 1/2*n [n is the total number of terms] *(2a [a is the value of the first term] + (n-1) * d)[d is the common difference between each term]So the formula looks like this: Sum = 1/2*n (2a+(n-1)*d)n = 50 because there's 50 odd numbers in a hundred and 50 even numbers (50+50=100)a = 1d = 2So inputting the values gives:Sum= 1/2*50 (2*1+(50-1)* 2)Sum= 25*(2+49*2)Sum= 25*(2+98)Sum= 25*(100)Sum= 2500Answer= 2,500
The sum of the composite numbers between 1 and 50 is 936.
51
The sum of 9 odd numbers must be odd and so cannot be an number.
The nine odd numbers whose sum is 50 are 1, 3, 5, 7, 9, 11, 13, 15, and 1.
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
The sum of the first 50 whole numbers is 1,225.
The sum of the first 50 natural numbers is 1,251.
over 50
140
328
The sum of the first 50 odd numbers is 2,500.