Sum of first n integers = n/2(n+1), in this case 25 x 51 = 1275
To find the 9 odd numbers whose sum is 50 from 1 to 50, we can first calculate the sum of all odd numbers from 1 to 50, which is (50^2)/2 = 625. Next, we subtract the sum of the first 9 odd numbers (1+3+5+7+9+11+13+15+17 = 81) from the total sum, resulting in 625 - 81 = 544. Therefore, the 9 odd numbers whose sum is 50 from 1 to 50 are 19, 21, 23, 25, 27, 29, 31, 33, and 36.
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
The sum of the first 50 whole numbers is 1,225.
Using the formula for the sum of an arithmetic sequence;Sum = 1/2*n [n is the total number of terms] *(2a [a is the value of the first term] + (n-1) * d)[d is the common difference between each term]So the formula looks like this: Sum = 1/2*n (2a+(n-1)*d)n = 50 because there's 50 odd numbers in a hundred and 50 even numbers (50+50=100)a = 1d = 2So inputting the values gives:Sum= 1/2*50 (2*1+(50-1)* 2)Sum= 25*(2+49*2)Sum= 25*(2+98)Sum= 25*(100)Sum= 2500Answer= 2,500
51
To find the 9 odd numbers whose sum is 50 from 1 to 50, we can first calculate the sum of all odd numbers from 1 to 50, which is (50^2)/2 = 625. Next, we subtract the sum of the first 9 odd numbers (1+3+5+7+9+11+13+15+17 = 81) from the total sum, resulting in 625 - 81 = 544. Therefore, the 9 odd numbers whose sum is 50 from 1 to 50 are 19, 21, 23, 25, 27, 29, 31, 33, and 36.
The nine odd numbers whose sum is 50 are 1, 3, 5, 7, 9, 11, 13, 15, and 1.
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
The sum of the first 50 whole numbers is 1,225.
The sum of the first 50 natural numbers is 1,251.
The sum of the first 50 even numbers is 2,550.
The sum of the first 50 odd numbers is 2,500.
over 50
328
140