It is 40*41/2 = 820
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Find three consecutive positive even integers whose sum is 123 , Answer
The numbers are 39 and 40.
-37
First integer divisible by 10 is 10 itself .So the numbers are 10,20,30,40 and so onthe sum is10+20+30+40+....+990+100010(1+2+3+4+.....+99+100)10*100*101/250500
The sum of the first 40 odd numbers is 1,600.