Find three consecutive positive even integers whose sum is 123 , Answer
The numbers are 39 and 40.
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First integer divisible by 10 is 10 itself .So the numbers are 10,20,30,40 and so onthe sum is10+20+30+40+....+990+100010(1+2+3+4+.....+99+100)10*100*101/250500
The sum of the first 40 odd numbers is 1,600.
The sum of the first 40 even positive integers can be equal to 820.
The sum of the first forty positive integers can be calculated using the formula for the sum of an arithmetic series, which is (n/2)(first term + last term) where n is the number of terms. In this case, the sum is (40/2)(1 + 40) = 820.
75 = 40 + 35
No. There is no set of three consecutive even integers with a sum of 40.
Find three consecutive positive even integers whose sum is 123 , Answer
The integers are 39 and 40.
The two integers are A and A+40 or, equivalently, B and B-40.
The integers are 40, 41 and 42.
Half it = 41, so consecutive even integers are 40 & 42
The numbers are 39 and 40.
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38, 39, 40