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1275.
Why the formula works:
The formula for the first n integers comes from the following idea.
Make a list of all n integers, let us just say 5 to make it easy to see.
1,2,3,4,5
Now write them again , but start with 5.
5,4,3,2,1
Now write them one on top of the other
1,2,3,4,5
5,4,3,2,1
If you add those two lists, column by column, each column has a total of 6.
5+1, 4+2, 3+3 etc.
And since it was the numbers 1-5, there are 5 columns.
So we have 5x6 as a total so far. But we counted each number twice sine we wrote them twice. So now to fix that we need to divided by2 and we have 5x6 divided by2=15
The general formula for the first n integers starting with 1 is
n(n+1)/2
So in this case it is (50)(51)/2=51x25=1275
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Sum the integers from 1 to 100?
The sum of the integers from 1 to 100 inclusive is 5,050.
What is the sum of the numbers from 1 to 50?
Sum of first n integers = n/2(n+1), in this case 25 x 51 = 1275
What is the sum of the first 50 natural numbers?
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
What is the sum of integers from 1 to 2008?
The sum of integers from 1 to 2008 = 2008*2009/2 = 2017063
What is the sum of 50 greatest negative integers?
i got the same question for homework in functions. tn=a+(n-1)d -50=-1+(n-1)-1 -50=-1-1n+1 -50=-1n therefore n=50 plug that into your sum equation...for convenience i used Sn=50/2 (-1-50) Sn=25 (-51) Sn= -1275 hope this helps!
Sum the integers from 1 to 100?
The sum of the integers from 1 to 100 inclusive is 5,050.
The sum of all the integers between 50 to 350 which end in 1 is?
If you write down all of the integers between the two numbers, your sum is equivalent to 5,659.
What is the sum of the numbers from 1 to 50?
Sum of first n integers = n/2(n+1), in this case 25 x 51 = 1275
What is the sum of the first 50 natural numbers?
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
What is the sum of integers from 1 to 2008?
The sum of integers from 1 to 2008 = 2008*2009/2 = 2017063
What is the sum of all integers from 1 to 20?
The sum of all integers from 1 to 20 inclusive is 210.
What is the sum off all integers from -10 to 2012 inclusive?
sum -10 to -1 = -55; sum 1 to 2,012 = 2,013 x 1,006 = 2,025,078 total 2,025,023
What is the sum of the integers from 1to 300?
The sum of the integers from 1 through 300 is 44,850.
Is 95 the sum of integers between 1 and 500?
No. The sum of all integers between 1 and 500 is 124,749.
What is the sum of all consecutive integers 1-100?
101
What is the sum of 50 greatest negative integers?
i got the same question for homework in functions. tn=a+(n-1)d -50=-1+(n-1)-1 -50=-1-1n+1 -50=-1n therefore n=50 plug that into your sum equation...for convenience i used Sn=50/2 (-1-50) Sn=25 (-51) Sn= -1275 hope this helps!
What is the sum of the integers from 1 to 300?
(300 x (300 + 1)) / 2 = 45150 Therefore, the sum of all the integers from 1 to 300 is 45150.
