0
1275.
Why the formula works:
The formula for the first n integers comes from the following idea.
Make a list of all n integers, let us just say 5 to make it easy to see.
1,2,3,4,5
Now write them again , but start with 5.
5,4,3,2,1
Now write them one on top of the other
1,2,3,4,5
5,4,3,2,1
If you add those two lists, column by column, each column has a total of 6.
5+1, 4+2, 3+3 etc.
And since it was the numbers 1-5, there are 5 columns.
So we have 5x6 as a total so far. But we counted each number twice sine we wrote them twice. So now to fix that we need to divided by2 and we have 5x6 divided by2=15
The general formula for the first n integers starting with 1 is
n(n+1)/2
So in this case it is (50)(51)/2=51x25=1275
What else can I help you with?
Sum the integers from 1 to 100?
The sum of the integers from 1 to 100 inclusive is 5,050.
What is the sum of the numbers from 1 to 50?
Sum of first n integers = n/2(n+1), in this case 25 x 51 = 1275
What is the sum of the first 50 natural numbers?
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
What is the sum of integers from 1 to 2008?
The sum of integers from 1 to 2008 = 2008*2009/2 = 2017063
What is the sum of 50 greatest negative integers?
i got the same question for homework in functions. tn=a+(n-1)d -50=-1+(n-1)-1 -50=-1-1n+1 -50=-1n therefore n=50 plug that into your sum equation...for convenience i used Sn=50/2 (-1-50) Sn=25 (-51) Sn= -1275 hope this helps!
The sum of all the integers between 50 to 350 which end in 1 is?
If you write down all of the integers between the two numbers, your sum is equivalent to 5,659.
Sum the integers from 1 to 100?
The sum of the integers from 1 to 100 inclusive is 5,050.
What is the sum of the numbers from 1 to 50?
Sum of first n integers = n/2(n+1), in this case 25 x 51 = 1275
What is the sum of the first 50 natural numbers?
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
What is the sum of integers from 1 to 2008?
The sum of integers from 1 to 2008 = 2008*2009/2 = 2017063
What is the sum of all integers from 1 to 20?
The sum of all integers from 1 to 20 inclusive is 210.
What is the sum off all integers from -10 to 2012 inclusive?
sum -10 to -1 = -55; sum 1 to 2,012 = 2,013 x 1,006 = 2,025,078 total 2,025,023
What is the sum of the integers from 1to 300?
The sum of the integers from 1 through 300 is 44,850.
Is 95 the sum of integers between 1 and 500?
No. The sum of all integers between 1 and 500 is 124,749.
What is the sum of 50 greatest negative integers?
i got the same question for homework in functions. tn=a+(n-1)d -50=-1+(n-1)-1 -50=-1-1n+1 -50=-1n therefore n=50 plug that into your sum equation...for convenience i used Sn=50/2 (-1-50) Sn=25 (-51) Sn= -1275 hope this helps!
What is the sum of all consecutive integers 1-100?
101
What is the mean of the first 100 integers?
The mean of the first 100 integers can be calculated by finding the sum of these integers and dividing by the total count. The sum of the first 100 integers (from 1 to 100) is ( \frac{100(100 + 1)}{2} = 5050 ). Dividing this by 100 gives a mean of ( \frac{5050}{100} = 50.5 ). Therefore, the mean of the first 100 integers is 50.5.
