i got the same question for homework in functions.
tn=a+(n-1)d
-50=-1+(n-1)-1
-50=-1-1n+1
-50=-1n
therefore n=50
plug that into your sum equation...for convenience i used
Sn=50/2 (-1-50)
Sn=25 (-51)
Sn= -1275
hope this helps!
They total 650. * * * * * It is 2550.
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
Sum of first n integers = n/2(n+1), in this case 25 x 51 = 1275
49+50+51=150 General rule for this kind of question: divide the number you're trying to obtain (150) by the number of integers you're allowed (3), and then simply add one and subtract one until you have the specified number of integers.
50
50
810. All of the integers from -30 to30 cancel each other out by adding a negative to a positive. Then all you need to do is add the integers from 31 to 50. (31 + 32 + ....+50)
-15
5 & 10
The integers are 49 and 50.
1275
no solultion!
It can be.
50, 51, 52
If you write down all of the integers between the two numbers, your sum is equivalent to 5,659.
They total 650. * * * * * It is 2550.
50 + 51 + 52 = 153