You can find the surface area of a sphere by solving this equation: SA=4(pi)(r)(r) where SA is your surface area, and r is the radius.
Your answer comes out to be about 1017.4 square units.
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Surface area = 4 pi * r**2
so with radius 9, the surface area = 324 * pi ~= 1017.876
A sphere with a radius of 9 units has a volume of 3,053.63 units3
These dimensions are not possible for a right cone. The radius must be less than the slant height. If we reverse the dimensions (radius 6, slant height 9) the total surface area will be about 282.74 units2
The cross section at this point forms a circle and its area is pi/32 which equals 9*pi square units. * * * * * Not quite. If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 32) Therefore the cross sectional area is pi*(R2 - 32) square units.
The surface area of a sphere is 4 x pi x r x r so in our case (since we have only half a sphere (hemisphere) the surface ares would be (0.5) x 4 x pi x 9 x 9 =162 x pi square cm. But now you have to add the area of the base because it gets exposed when youcuta sphere (to get the hemisphere) and the area of the base would be pi x r x r = pi x 9 x 9 = 81 x pi square cm. So add the two results to get 243 x pi = 763.4 square cm
A cone with the radius of 5 cm and slope height of 9 cm has a total surface area of approximately 219.91cm2