Assuming you mean y=2x(24x-100)=48x2-200x
The vertex is the coordinate (p,q) when a function of a form y=ax2+bx+c is arranged into the form y=a(x-p)2+q.
Divide y by the coeifficient of the x2 term, 48. y = x2-(25/6)x
x2-ax = (x-a/2)2-a2/4.
So y = [x-(25/6)/2]2-(625/36)/4 = [x-25/12]2-625/144
y is now in the form y=a(x+p)2+q, so the vertex of 48x2-200x is (25/12, -625/144)
It is the equation of a parabola.
When x = -5
The slope is -4
yes
11
Line of symmetry: x = 3
The equation does not represent that of a parabola.
It is the equation of a parabola.
It is the parabola such that the coordinates of each point on it satisfies the given equation.
No you can't. There is no unique solution for 'x' and 'y'. The equation describes a parabola, and every point on the parabola satisfies the equation.
1/([*sqrt(cx)]
X equals 0.5at squared is a quadratic equation. It describes a parabola. Y equals mx plus b is a linear equation. It describes a line. You cannot describe a parabola with a linear equation.
An equation of a parabola in the x-y plane, is one possibility.
At: x = 6
There is no "equals" sign therefore "x-9" is NOT an equation.
When x = -5
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).