To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
Oh, what a happy little question! To find the area of a shape with sides of 7m, 4m, 5m, and 3m, we need to know the shape. If it's a rectangle, you can multiply the length (7m) by the width (4m) to get the area. If it's a triangle, you might need to use the formula for the area of a triangle. Just remember, there are no mistakes, only happy accidents in math and art!
You simply multiply width x height x length so: 7 x 4 x 2.4 = 78.4 cubic meters the answer is 67.2 m3
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
32 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (9) + 2 (7) = 18 + 14 = 32 also: P = 2 (L + W) 2(9 + 7) = 32
To find the area of a rectangle, you multiply the length by the width. In this case, the length is 7 meters and the width is 4 meters. Therefore, the area of a 7m by 4m rectangle is 28 square meters.
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m
Well, isn't that just a lovely rectangle you have there, friend! To find the perimeter, you simply add up all the sides. So for a rectangle that is 4 meters by 7 meters, you would add 4 + 4 + 7 + 7 to get a perimeter of 22 meters. Just imagine all the happy little footsteps that could walk around that beautiful rectangle!
Rectangle with area 28 m2 and width = 4 m => length = 28/4 = 7m. Then, perimeter = 2*(4+7) = 2*11 = 22 metres.
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
-(4m + 3)(5m - 2)
Oh, what a happy little question! To find the area of a shape with sides of 7m, 4m, 5m, and 3m, we need to know the shape. If it's a rectangle, you can multiply the length (7m) by the width (4m) to get the area. If it's a triangle, you might need to use the formula for the area of a triangle. Just remember, there are no mistakes, only happy accidents in math and art!
4/7 - 4/m need a common denominator--multiply the first term by m/m and the second by 7/7 4m/7m - 28/7m (4m-28)/7m OR 4/7 - 4/m
4m + 3m = 180 7m = 180 m = 25 5/7
Every one of them could be a side of a rectangle. It is not possible to give an answer in respect of an unspecified rectangular object. however, i feel the question is incorrect as it should be sides of the triangle and according to it 3rd is the answer as 3+5<9 :)
The area of rectangle is : 56.0
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.