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2x - 3y = 14

2x - y = 10

eqn (1) - eqn(2) gives: -2y = 4 so that y = -2

Then, by eqn (2): 2x -(-2) = 10

2x + 2 = 10

2x = 8 and so x = 4

The solution, therefore, is (x, y) = (4, -2)

2x - 3y = 14

2x - y = 10

eqn (1) - eqn(2) gives: -2y = 4 so that y = -2

Then, by eqn (2): 2x -(-2) = 10

2x + 2 = 10

2x = 8 and so x = 4

The solution, therefore, is (x, y) = (4, -2)

2x - 3y = 14

2x - y = 10

eqn (1) - eqn(2) gives: -2y = 4 so that y = -2

Then, by eqn (2): 2x -(-2) = 10

2x + 2 = 10

2x = 8 and so x = 4

The solution, therefore, is (x, y) = (4, -2)

2x - 3y = 14

2x - y = 10

eqn (1) - eqn(2) gives: -2y = 4 so that y = -2

Then, by eqn (2): 2x -(-2) = 10

2x + 2 = 10

2x = 8 and so x = 4

The solution, therefore, is (x, y) = (4, -2)

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12y ago

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